In a sample of 100 atoms of Boron, there are 20 atoms of Boron – 10 and 80 atoms of Boron – 11.
(i) Explain why these two forms of Boron are isotopes?
(ii) Calculate the relative atomic mass of Boron.
(ii) Calculate the relative atomic mass of Boron.
Isotopes
i) they have different number of neutrons but similar number of protons and electron
ii) ((80 x 11) + (20 x 10))/100 = 10.2
i) should use same instead of similar
ii) Calculation error using the calculator. Answer should be 10.8
(i)The two forms of boron have different number of neutrons but same number of protons.
(ii) ((80/100)x11) +((20/100)×10)= 10.8
i) Same element with same number of protons and electrons but different number of neutrons.
ii) Correct!
(i)Isotopes are the atoms of the same element but with different number of neutrons but the same number of protons.
(ii) [ (20 x 10) + (80 x 11) ] /100 =9
i) Great!
ii) Calculation error using calculator. Answer should be 10.8